Waec gce 1st Series 2022 Chemistry Question And Answers
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Paper III & II: Objective & Essay – Chemistry – 9:30pm – 12:30pm
OBJ ANSWERS
1ABCDBBCBDD
11BAACDDCBAA
21CCACBCADDD
31ACADCBBACB
41DBBADADDCB
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THEORY ANSWERS
(1ai)
Electrolysis is the process by which ionic substances are decomposed (broken down) into simpler substances when an electric current is passed through them.
(1aii)The concentration of ion.
(1b)Rate of Chemical Reaction is the speed at which a chemical reaction proceeds. It is often expressed in terms of either the concentration (amount per unit volume) of a product that is formed in a unit of time or the concentration of a reactant that is consumed in a unit of time.
(1c)
The iodide ions are less electronegative than chloride ions and so they are better reducing agents than chloride ions.
(1di)
3Cl + 6NaOH - -> NaClO₃ + 5NaCl + 3H₂O
(1dii)
Oxidation reaction
(1ei)
CₙH₂ₙ₊₁ COOH = 74
12n +2n +1 +12 +16 +15 +1 =74
14n + 46 =74
14n = 28
n = 2
= CₙH₂ₙ₊₁COOH
= C₂H₄₊₁COOH
= C₂H₅COOH
H H OH
| | |
H - C - C - C =O
| |
H H
(1eii)
Propanoic Acid
(1fi)
This is because of its polarity and ability to form hydrogen bonds therefore it dissolves different molecules.
(1fii)
Sulphur dioxide being a strong reducing agent, reduces the purple coloured solution to form a colourless solution.
(1gi)
(1gii)
Methane
(1giii)
Double decomposition
(1hi)
Solution of silver trioxonitrate(v)
(1hii)
Oxidation reaction
Electrolysis is the process by which ionic substances are decomposed (broken down) into simpler substances when an electric current is passed through them.
(1aii)The concentration of ion.
(1b)Rate of Chemical Reaction is the speed at which a chemical reaction proceeds. It is often expressed in terms of either the concentration (amount per unit volume) of a product that is formed in a unit of time or the concentration of a reactant that is consumed in a unit of time.
(1c)
The iodide ions are less electronegative than chloride ions and so they are better reducing agents than chloride ions.
(1di)
3Cl + 6NaOH - -> NaClO₃ + 5NaCl + 3H₂O
(1dii)
Oxidation reaction
(1ei)
CₙH₂ₙ₊₁ COOH = 74
12n +2n +1 +12 +16 +15 +1 =74
14n + 46 =74
14n = 28
n = 2
= CₙH₂ₙ₊₁COOH
= C₂H₄₊₁COOH
= C₂H₅COOH
H H OH
| | |
H - C - C - C =O
| |
H H
(1eii)
Propanoic Acid
(1fi)
This is because of its polarity and ability to form hydrogen bonds therefore it dissolves different molecules.
(1fii)
Sulphur dioxide being a strong reducing agent, reduces the purple coloured solution to form a colourless solution.
(1gi)
(1gii)
Methane
(1giii)
Double decomposition
(1hi)
Solution of silver trioxonitrate(v)
(1hii)
Oxidation reaction
(1i)
The first Ionization of Nitrogen is higher than that of Oxygen because of the inner screening effect in the nucleus of Nitrogen conferring higher Ionization energy.
(1j)
3- Methylpropane
The first Ionization of Nitrogen is higher than that of Oxygen because of the inner screening effect in the nucleus of Nitrogen conferring higher Ionization energy.
(1j)
3- Methylpropane
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